计算元空间轮廓是否和楼层轮廓是否有重叠
# 前置条件
    1. 元空间和楼层必须都有轮廓
    2. 轮廓必须符合规则
    
# 处理逻辑

    将楼层的外轮廓与元空间的最外层轮廓做是否重叠检查操作

# 函数

<details>
<summary>源码</summary>

```
CREATE OR REPLACE FUNCTION "public"."other_ispace_floor_overlap"("ispace_outline" jsonb, "floor_outline" jsonb)
  RETURNS "pg_catalog"."bool" AS $BODY$

from shapely.geometry import Polygon
import json

# 获取Polygon对象
def get_polygon(single_poly):
    poly_len = len(single_poly)
    poly = []
    for i in range(poly_len):
        pair = single_poly[i]
        poly.append((pair["X"], pair["Y"]))
    return Polygon(poly)

try:
    if ispace_outline is None or floor_outline is None:
        return False
    ispace_json = json.loads(ispace_outline)
    floor_json = json.loads(floor_outline)
    if len(floor_json) < 3 or len(ispace_json) == 0 or len(ispace_json[0]) < 3 :
        return False
    ispace_poly = get_polygon(ispace_json[0])
    floor_poly = get_polygon(floor_json)
    if floor_poly.contains(ispace_poly) or floor_poly.equals(ispace_poly) or floor_poly.overlaps(ispace_poly):
        return True
    return False
except Exception as e:
    #plpy.warning(e)
    return False

$BODY$
  LANGUAGE plpython3u VOLATILE
  COST 100

```

</details>

## 输入
    1. 元空间轮廓
    2. 楼层轮廓
## 返回结果
    true    有重叠
    false   未重叠